(8x^2-4x-4)/2

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Solution for (8x^2-4x-4)/2 equation: 


x in (-oo:+oo)

(8*x^2-(4*x)-4)/2 = 0

(8*x^2-4*x-4)/2 = 0

8*x^2-4*x-4 = 0

4*(2*x^2-x-1) = 0

2*x^2-x-1 = 0

DELTA = (-1)^2-(-1*2*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(2*2) or x = (1-9^(1/2))/(2*2)

x = 1 or x = -1/2

4*(x+1/2)*(x-1) = 0

(4*(x+1/2)*(x-1))/2 = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -1/2, 1 }

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